Question

Calculate the first and second velocities of the car with two washers attached to the pulley, using the formulas

v1 = 0.25 m / t1, and

v2 = 0.25 m / (t2 – t1)

where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, to two decimal places, in Table E.

What is the first velocity of the car with two washers at the 0.25 meter mark?

m/s

What is the second velocity of the car with two washers at the 0.50 meter mark?

m/s

Answer 1

Answer:

Calculate the first and second velocities of the car with two washers attached to the pulley, using the formulas

v1 = 0.25 m / t1, and

v2 = 0.25 m / (t2 – t1)

where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, to two decimal places, in Table E.

What is the first velocity of the car with two washers at the 0.25 meter mark?

m/s

What is the second velocity of the car with two washers at the 0.50 meter mark?

m/s

Answer 2

Hence, the 1st velocity of the car is 0.25 m/s and the 2ndvelocity of the car is 0.50 m/s.

Given:

v1 = 0.25 m / t1

v2 = 0.25 m / (t2 - t1)

To find:

First velocity of the car and 2nd velocity of the car.

Solution:

For calculating velocities of the car , we can use the given formula,

v1 = 0.25 m / t1

v2 = 0.25 m / (t2 - t1)

Here

t1 and t2 = average times.

Consider the car takes time , t1 = 1.0 s for reaching 0.25 m  

                                                t2 = 1.5 s for reaching 0.50 m.

Now after putting the values in the formula,

   v1 =$\frac{ 0.25 m }{ t1}$

⇒v1 = $\frac{0.25 m}{1.0 s}$

⇒v1 = 0.25 m/s

Here the first velocity of the car is 0.25 m/s.

Now using 2nd formula,

⇒v2 = $\frac{0.25 m }{(t2 - t1)}$

⇒v2 = $\frac{0.25 m}{(t2 - t1)}$

⇒v2 = $\frac{0.25 m }{ 0.5 s}$

⇒v2 = 0.50 m/s

Here the 2nd velocity of the car is 0.50 m/s.

Hence ,the 1st velocity of the car is 0.25 m/s and the 2ndvelocity of the car is 0.50 m/s.

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