Calculate the first and second velocities of the car with one washer attached to the pulley, using the formulas
v1 = 0.25 m / t1, and
v2 = 0.25 m / (t2 – t1)
where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, rounded to two decimal places, in Table E.
What is the first velocity of the car with one washer at the 0.25 meter mark?
Answers
Calculate the first and second velocities of the car with one washer attached to the pulley, using the formulas
v1 = 0.25 m / t1, and
v2 = 0.25 m / (t2 – t1)
where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, rounded to two decimal places, in Table E.
What is the first velocity of the car with one washer at the 0.25 meter mark?
Answer to the question is:
If v1 is 0.25 and v2 is 0.25 then adding v1 and v2, We will get o.50. hence it is the answer.
Explanation:
Time passed before the speed change
speed = d1/t1 ;
65 mi/h = (130 mi)/t1
t1 = 2.0 h.
the time at the lower speed is
t2 = T — t1 = 3.33 h — 2.0 h = 1.33 h.
We discover the separation went at the lower speed from
speed = d2/t2;
55 mi/h = d2/ (1.33 h), which gives d2 = 73 mi.
The complete separation =
D = d1 + d2 = 130 mi + 73 mi = 203 mi.
normal speed = d/t = (203 mi)/(3.33 h) = 61 mi/h.
Note that the normal speed isn’t!
(65 mi/h + 55 mi/h). The two rates were not kept up for
break even with times