Question

calculate the focal distance of point P on the parabola Y2=20x whose ordinate is 10​

Answer 1

Step-by-step explanation:therefore the focal distance off point p on the the parabola y square is equals to 20 X whose ordinate is 10.

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Answer 2

Answer:

Focal distance PF = 25 cm.

Step-by-step explanation:

Given that ,

the focal distance of point P on the parabola Y2=20x whose ordinate is 10​.

As per given data,

$y^{2} = 20x$

$y^{2}= (4)(5)x$

$where~a=5.$

Point P (0,10).

and F ( 5,0)

So, focal distance PF = $\sqrt{((0-5)^{2}+(10-0)^{2} }$

                                  = $\sqrt{25 + 100}$

                                  = $\sqrt{125}$

                             PF = 25 units.

Therefore, the focal distance PF = 25 cm.

Formula of Right-handed Parabola,

$y^{2}= 4ax , a > 0~is ~ a~parabola~whose\\ (i)~focus~is~F(a,0)\\(ii) ~vertex~is~O(0,0)\\(iii) ~directrix~is~the~line~x+a=0\\(iv)~axis~is~the~line~x+a=0\\(v)~length~of~the~latus~rectum~is~4a\\(vi) ~latus~rectum~is~the~line~x=a.$

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