Question

Calculate the following quantities in 5.6 g of Nitrogen (Atomic mass of Nitrogen=14u)
a. Number of moles of N2
b. Number of molecules of N2
c. Number of atoms of nitrogen

Answer 1

Answer:

a) 0.4 moles

b) 2.4×10^23 molecules

c) 4.8×10^23 atoms

Explanation:

a)  no of moles = given wt./ mwt.

              n= 5.6/14 =0.4 moles

b) N = n ×NA

        0.4× (6.023×10^23)

   N= 2.4×10^23 molecules

c) one molecule contains 2 atoms of nitrogen

therefore 2×N will be the no. of atoms

4.8×10^23 atoms

Answer 2

Answer:

a) 0.4 moles

b) 2.4×10^23 molecules

c) 4.8×10^23 atoms

Explanation:

a)  no of moles = given wt./ mwt.

             n= 5.6/14 =0.4 moles

b) N = n ×NA

       0.4× (6.023×10^23)

  N= 2.4×10^23 molecules

c) one molecule contains 2 atoms of nitrogen

therefore 2×N will be the no. of atoms

4.8×10^23 atoms