Physics, asked by indianboy21, 4 months ago

calculate the following ques​

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Answers

Answered by kritanuchatterjee280
1

Answer:

1) 24.4° 2) 1.33

Explanation:

i) RI = 1/sin C where C = critical angle

2.42 = 1/sin C

sin C = 1/2.42

sin C = 100/242

C = sin⁻¹(100/242)

C= 24.4°

ii)

speed of light in water =2.25 X 10 ⁸ m/s

speed of light in vacuum = 3 X 10⁸ m/s

RI of water = 3 X 10⁸ m/s / 2.25 X 10⁸ m/s

                  =  1.33

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