calculate the for e of attraction between a 80 kg man and the earth . mass of the earth is 6×10^24 kg, radius of the earth is 6.4×10^3
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Answer:
Mass of man = 80 kg
Mass of the earth = 6 \times 10^246×10
2
4 kg
Radius of the earth = 6.4 \times 10^66.4×10
6
m
Force = \frac{G \times M_e \times m}{R^2}Force=
R
2
G×M
e
×m
Force = \frac{6.67 \times 10^-^1^1 \times 6 \times 10^2^4 \times 80}{(6.4 \times 10^6)^2}
Force = 781.6 Newtons
Hence, the force of attraction between the man and the earth is 781.6
Explanation:
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