Question

calculate the for e of attraction between a 80 kg man and the earth . mass of the earth is 6×10^24 kg, radius of the earth is 6.4×10^3

Answer 1

Mass of man = 80 kg

Mass of the earth = $6 \times 10^24$ kg

Radius of the earth = $6.4 \times 10^6$m

$Force = \frac{G \times M_e \times m}{R^2}$

$Force = \frac{6.67 \times 10^-^1^1 \times 6 \times 10^2^4 \times 80}{(6.4 \times 10^6)^2}$

Force =  781.6 Newtons

Hence, the force of attraction between the man and the earth is 781.6 N