Question

Calculate the force applied on a body producing a moment of force of 16 Nm such that the
perpendicular distance between the point of application of force and the turning point is 80 cm.​

Answer 1

Answer:

20n

Explanation:

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Answer 2

Answer:

20N

Explanation:

Given :

Moment of force is 16Nm that a perpendicular distance between the point of application of force and the turning point is 80 cm

To Find :

Force = ?

Solution :

The moment formula is given by

Moment of force = F x d

Here,

F is the force applied,

d is the distance from the fixed axis,

Moment of force = 16Nm.

Distance between the point of application of force from and the turning point is = 80cm = 0.8m. [1cm = 1/100]

$\sf{}Moment\ of\ force(F)=Force(f)\times Distance\ from\ the\ fixed\ axis(d)$

$\sf{}Force(f)=\dfrac{Moment\ of\ force(F)}{Distance\ from\ the\ fixed\ axis(d)}$

$\sf{}\implies f=\dfrac{F}{d}$

$\sf{}\implies f=\dfrac{16}{0.8}$

$\sf{}\therefore f=20N$

Therefore, the force applied on the body is 20N.