Question

calculate the force applied to a body of mass 100 kg moving with the velocity 20 m/s so that it can be brought into rest in 5 seconds.

Answer 1

Answer:

F = - 400 N

Explanation:

Mass, m = 100 kg

Initial Velocity, u = 20 m/s

Final Velocity, v = 0 m/s

t = 5 sec

F = m(v-u)/t

F = 100(0 - 20)/5

F = 100 * (-20)/5

F = -100 * 4

F = -400 N

Answer 2

Step By Step Explanation:

M= 100Kg

Initial Velocity(u)=20m/s

Final Velocity(v)=0(because it comes to rest)

Time= 5 seconds

Therefore Acceleration(a) = v-u/t

= 0 m/s -20 m/s/5s

= -4m/s

We know that Force(F) = Ma, Therefore

F= 20Kg × -4 m/s²

= -80N