Physics, asked by chemdruid7123, 8 months ago

Calculate the force between 7uc and 3uc separated by 3 mm

Answers

Answered by darshangoswami25
0

answer:21000N

Explanation:

formula: F=kqq/r2

Answered by TheValkyrie
1

Hi,

Here is your answer

Given:

First charge(Q1)=7μC=7×10⁻⁶C

Second charge(Q2)=3μC=3×10⁻⁶C

Separation between charges(r)=3mm=0.003m

To find:

Force between the charges

Solution:

By Coulomb's law

F=kQ1Q2/r²

where k=9×10⁹Nm²/C²

Substituting the given datas, we get

F=9×10⁹×7×10⁻⁶×3×10⁻⁶/(0.003)²

F=21×10³C

Notes:

1.Remember to convert all the given datas to their SI units before calculating.

2.Coulomb's law state that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

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