Calculate the force between 7uc and 3uc separated by 3 mm
Answers
Answered by
0
answer:21000N
Explanation:
formula: F=kqq/r2
Answered by
1
Hi,
Here is your answer
Given:
First charge(Q1)=7μC=7×10⁻⁶C
Second charge(Q2)=3μC=3×10⁻⁶C
Separation between charges(r)=3mm=0.003m
To find:
Force between the charges
Solution:
By Coulomb's law
F=kQ1Q2/r²
where k=9×10⁹Nm²/C²
Substituting the given datas, we get
F=9×10⁹×7×10⁻⁶×3×10⁻⁶/(0.003)²
F=21×10³C
Notes:
1.Remember to convert all the given datas to their SI units before calculating.
2.Coulomb's law state that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Similar questions