Calculate the force between two alpha particles kept at a distance of 0.02mm in air.
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alpha particles hav +2e charge.. force= kq1q2/r
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Answer:
1.44 × (10^-18)
Explanation:
for an alpha particle charge = 2 × charge of an electron
distance between them is 0.002mm = 2×10∧-5 m
we know the formula F=(1/4πε ×q1×q2)/r²
thus
F= {(9×10∧9)×(2²)×(1.6×10∧-19)²}÷{(2×10∧-5)²}
F=1.44 × (10^-18)
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