calculate the force between two charge each of 20 micro coulombs in a medium of relative permittivity 4. the distance between the two charge is 40cm
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Answer:
Step-by-step explanation:
F = 20×20×10^-12/4*4*22/7*absilonzero*16×10^-2
F= 400×10^-12/16×16pie*10^-2
F= 4×10^-8/16pie
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