Question

calculate the force between two charge each of 20 micro coulombs in a medium of relative permittivity 4. the distance between the two charge is 40cm

Answer 1

Answer:

Step-by-step explanation:

F = 20×20×10^-12/4*4*22/7*absilonzero*16×10^-2

F= 400×10^-12/16×16pie*10^-2

F= 4×10^-8/16pie