Calculate the force between two point charge of 2 coulomb each separate by a distance of 2m in vacuum.
Answers
The ratio of Coulomb force to gravitational force for an electron and a proton is given as,
r
1
=
R
2
Gm
1
m
2
4πε
0
1
×
R
2
q
1
q
2
=
6.67×10
−11
×9.1×10
−31
×1.67×10
−27
9×10
9
×(1.6×10
−19
)×(1.6×10
−19
)
=
1
2.27×10
39
The ratio of Coulomb force to gravitational force for two protons is given as,
r
2
=
R
2
Gm
2
4πε
0
1
×
R
2
q
1
q
2
=
6.67×10
−11
×(1.67×10
−27
)
2
9×10
9
×(1.6×10
−19
)×(1.6×10
−19
)
=
1
1.24×10
36
(b)
The magnitude of Coulomb force between electron and proton is given as,
F=
4πε
0
1
×
R
2
q
1
q
2
=
(10
−10
)
2
9×10
9
×(1.6×10
−19
)×(1.6×10
−19
)
=2.304×10
−8
N
The acceleration of electron is given as,
a
1
=
m
1
F
=
9.1×10
−31
2.304×10
−8
=2.5×10
22
m/s
2
The acceleration of proton is given as,
a
2
=
m
2
F
=
1.67×10
−27
2.304×10
−8
=1.4×10
19
m/s
2
Answer:
calculate the force between two point change s of 2c each separate d by a distance of 2m in a vaccum