Question

calculate the force exerted by friction if an object of mass 25 kg is applied with force of 12 Newton and accelerates at the rate of 0.2 metre per second square​

Answer 1

Explanation:

refer hc verma for clarity in concepts because physics is concepts

Answer 2

The force exerted by friction is 7 N.

Explanation:

Given mass of an object,     m = 25 kg

Applied force on an object,$F_{applied}=12N$

Acceleration of an object, a = 0.2 m/s^2

The relation between applied force when it applies on an object and frictional force is given by

$F=F_{applies} -F_{frictional}$

Here, F is net force on an object.

As per Newton`s second law,

F = ma

So, $ma=F_{applies} -F_{frictional}$

Substitute the given values, we get

$25kg\times0.2m/s^2=12N-F_{frictional}$

$F_{frictional}=12N-5N=7N$

Thus, the force exerted by friction is 7 N.

Topic: Applied force and frictional force

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