Calculate the force exerted by the brakes on the motorcar which is moving with a velocity of 72 km/h and takes 5 s to stop after the application of brakes. Mass of the motorcar along with the passengers is 800 kg.
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Answer:
u = 72 km/hr = 20 m/s
v = 0 m/s
t = 5 s
a = \frac{v - u}{t} = \frac{0 - 20}{5} = - 4 \: m {s}^{ - 2}
Here, the - sign indicates that the body is retarding.
Mass = 800 kg.
force = mass \times acceleration
= 800 \times 4 = 3200 \: n
Therefore , the force applied by the brakes is 3200 N.
I hope it helps you.
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