Question

calculate the force exerted by the Earth on the Moon if mass of the earth is 6 into 10 to the power 24 kg and the mass of the moon is 7.4 into 10 to the power 22 kg distance between them is 3.84 into 10 to the power 5 kilometre and gravitational constant equal to 6.67 into 10 to the power minus 11 Newton metre square by kg square ​

Answer 1

Answer:

Step-by-step explanation:

Given Conditions ⇒

Mass of the Earth(m₁) = 6 × 10²⁴ kg.

Mass of the Moon(m₂) = 7.4 × 10²² kg.

Distance between the Earth and the Moon(d) = 3.84 × 10⁵ km.

 = 3.84 × 10⁸ m.

Gravitational Constant(G) = 6.7 × 10⁻¹¹ Nm²/kg².

Using the Newton's law of Gravitation,

 F = G × m₁×  m₂ × /d².

F is the Force of Gravitation between the Earth and the Moon.

Substituting the Given Values in the Formula,

∴ F = (6.7 × 10⁻¹¹ × 6 × 10²⁴ × 7.4 × 10²²) ÷ (3.84 × 10⁸)²

⇒ F = (6.7 × 6 × 7.4 × 10¹⁹) ÷ (14.7456)

⇒ F = 20.1741 × 10¹⁹ N.

⇒ F ≈ 20.2 × 10¹⁹ N.

Thus, the Gravitational Force of Attraction between the Earth and the Sun is 20.2 × 10¹⁹ N.

Hope it helps.

Answer 2

Answer:

20.2 × 10¹⁹ N

Explanation:

Given :

Mass of earth = 6 × 10²⁴ kg

Mass of moon = 7.4 × 10²² kg

Distance between them = 3.84 × 10⁵ km = 3.84  × 10⁸ m

We have value of G = 6.7 × 10⁻¹¹ N m² kg⁻²

We have to find force :

We have :

F = G m₁ m₂ / r²

F = ( 6.7 × 10⁻¹¹ ) ( 6 × 10²⁴ ) ( 7.4 × 10²² ) / (  3.84 × 10⁸ )² N

F = 20.2 × 10¹⁹ N

Hence force exerted by the earth on the moon is 20.2 × 10¹⁹ N.