Question

Calculate the force exerted on a body of mass 10kg for 2s ,which raises it's from 3m/s to 15m/s.

Give full solution ......​

Answer 1

Given :

• Mass of Body (m) = 10 kg
• Time (t) = 2 s
• Initial velocity (u) = 3 m/s
• Final velocity (v) = 15 m/s

To Find :

• Force exerted on the body

Solution :

$\underbrace{\sf{Acceleration \: of \: Body}} \\ \\ \implies \sf{a \: = \: \dfrac{v \: - \: u}{t}} \\ \\ \implies \sf{a \: = \: \dfrac{15 \: - \: 3}{2}} \\ \\ \implies \sf{a \: = \: \dfrac{12}{2}} \\ \\ \implies \sf{a \: = \: 6}$

$\therefore$ Acceleration of the body is 6 m/s²

______________________________

$\underbrace{\sf{Force \: Exerted \: on \: body}} \\ \\ \implies \sf{F \: = \: ma} \\ \\ \implies \sf{F \: = \: 10 \: \times \: 6} \\ \\ \implies \sf{F \: = \: 60}$

$\therefore$ Force exerted on the body is 60 N

Answer 2

Given :-

• Initial velocity of a body (u)= 3m/s

• Final velocity (v)= 15m/s

• Time (t)= 2 seconds

• Mass of body (m) =10kg

To find :-

The Force exerted on a body

• Formula used !

$\bigstar{\boxed{\sf{Force = Mass \times Acceleration }}}$

$\bigstar{\boxed{\sf{Acceleration =\dfrac{v-u}{t} }}}$

$\longmapsto\sf Force = m\times a\\ \\ \longmapsto\sf force = m \times \bigg(\dfrac{v-u}{t}\bigg)\\ \\ \longmapsto\sf force = 10\times \bigg(\dfrac{15-3}{2}\bigg)\\ \\ \longmapsto\sf force = 10\times \bigg(\cancel{\dfrac{12}{2}}\bigg)\\ \\\longmapsto\sf force = 10\times 6\\ \\\longmapsto\sf force = 60N$

$\underline{\textsf{\textbf{\dag\ \ Force\ exerted \ on \ body = 60\ Newton}}}$