Question

Calculate the force exerted on a body of mass 10kg for 2s, which raises it's from 3m/s to 15m/s.​

Answer 1

Given :-

☛$\:\begin{cases}\sf\red{Initial\: velocity \:(u)\: =\: 3m/s}\\\sf\orange{Final\: velocity\:(v)\:=\:15m/s}\\\sf\blue{Time\:=\:2\: seconds}\\\sf\purple{Mass_{\:body}\:(m)\:=10kg}\end{cases}$

To find :-

• The $\bf\green{Force}$ exerted on a body

Formula Applied :-

☛$\:\begin{cases}\star\:{\sf{\red{Force}}} = {\sf{\orange{Mass}}} \times {\sf{\green{Acceleration}}} \\\\\star\:{\sf{\blue{Acceleration}}} ={\sf{\purple{\dfrac{v-u}{t}} }}\end{cases}$

Solution :-

$\to\:\:\sf{Force = m\times a }$

$\to\:\:\sf{Force = m \times \bigg(\dfrac{v-u}{t}\bigg) }$

$\to\:\:\sf{ Force = 10\times \bigg(\dfrac{15-3}{2}\bigg)}$

$\to\:\:\sf{Force = 10\times \bigg(\dfrac{12}{2}}\bigg)$

$\to\:\:\sf{Force = 10\times 6 }$

$\to\:\:\sf{ Force = 60}$

Hence,

$\star\:\sf\underline\red{Force\ exerted \ on \ body \ is \ {\bf{\pink{60 \ Newton}}}}$