Calculate the force
exerted on
the larger piston
of 20 cm²
area when
a force of ION acts on the smaller
piston of area 10 cm?
Answers
Answered by
0
Answer: This may help you
Explanation:
area A=10cm^2=10/1000 m^2
=10^-3m^2
pressure=thrust/area
=20N/10^-3m^2
=2*10^4 N m^-2
Answered by
0
Answer:
20N
Explanation:
pressure is same throughout the fluid
P1=p2
F1/A1=F2/A2
10/10=F/20
F=20N
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