calculate the force exerted on the motor cycle which is moving with the velocity of 72km/h and takes 5seconds to stop after the application of brakes mass of the motor cycle along with the passanger is 800kg
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Initial velocity, u = 72km/h = 20m/s
Final velocity, v = 0m/s
Time taken to stop, t = 5s
Mass of the motor car along the passengers, m = 800kg
Acceleration, a = [(v-u)/t]
= [(0-20)]/5]
= [-20/5]
= -4m/s^2
Force = m×a
= 800×(-4)
= (-2400)N
Opposing force is denoted by negative sign.
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