Question

Calculate the force exerted on the wall of a building perpendicular to the jet of water flowing out of a pipe of area of cross section 10-²m² with velocity of 15m/s assume that water does not rebound after striking the wall​

Answer 1

Explanation:

Here, v=15ms

−1

Area of cross section, A=10

−2

m

2

Density of water, ρ=10

3

kgm

−3

Mass of water hitting the wall per second

=ρ×A×v

=10

3

kgm

−3

×10

−2

m

2

×15ms

−1

=150kgs

−1

Force exerted on the wall= Momentum loss of water per second

=150kgs

−1

×15ms

−1

=2250N=2.25×10

3

N