Question

Calculate the force experienced by a conductor
of length 0.2 m carrying a current of 0.8 A,
when placed in a uniform magnetic field of
intensity 1.2 Wb/m2.​

Answer 1

Explanation:

Given: i=10A,B=0.15 T,θ=45

∘

and l=2 m

Force on a current carrying wire of finite length =

F

=l(

i

×

B

)

Hence, magnitude of force, F=Bilsinθ

=0.15×10×2×sin45

∘

=

2

3

N

Answer 2

Answer:

0.192N

Explanation:

given:

F???

I=0.8,. L=0.2METRE,. B= 1.2 WB/M²

SO,FORCE== I*(L*B)

PUTTING VALUES AND SOLVING IT WE CAN GET ANSWER 0.192 N

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