Question

Calculate the force experienced by a moving, electron while entering the space
between two parallel plates 0.1 m apart and at a potential difference of 300 V.
(Hint: Use E = V/d; & then F= =qE Ans.= 4.8x10-16 N)​

Answer 1

Answer:

as we know, E = V/d

then, E = 300/0.1 = 3000 N C⁻¹

now, F = qE                               (q =1.6 x 10⁻¹⁹ C)

⇒ F = (1.6 x 10⁻¹⁹ C) x (3 x 10³ N C⁻¹)

⇒ F = 4.8x10-16 N

PS: I hope this satisfies your query. Good luck!