Question

calculate the force experienced by an object of mass 500 g when work is 0.05 kj is done on it while moving along half a circle of radius 0.1 km​

Answer 1

Explanation:

500g=0.5kg . we know 1kgf=9.8n. so 0.5 kgf= 4.9n. so nm=j so distance covered is

44/7×100m= circumference.4400/7m=circumference 1/2 × 4400/7 is 2200/7m so energy output is 2200/7×4.9 is 1540 joules