Question

calculate the force if an object exerts pressure 50N/m sq. and area of contact is 0.2 meter sq.​

Answer 1

Gɪᴠᴇɴ :-

• Pressure (P) = 50 N/m²
• Area (A) = 0.2 m²

ᴛᴏ ғɪɴᴅ :-

• Force (F)

sᴏʟᴜᴛɪᴏɴ :-

We know that,

$\implies \sf \: Pressure(P) \: = \frac{Force(F)}{Area(A)} \\ \\ \\ \implies \sf \: P = \frac{F}{A}$

Put the above given values in it, we get,

$\implies \tt \: 50 = \frac{F}{0.2} \\ \\ \\ \implies \tt \: F = 50 \times 0.2 \\ \\ \\ \implies \tt \: F = 10N$

We get,

• Force (F) = 10N

Answer 2

$\bf{\underline{\underline {Solution:-}}}$

$\pink{\bf{Need\:To\:Find}\begin{cases}\sf{ \green{Force = \:10\:N}\: }\end{cases}}$

$\pink{\bf{Given}\begin{cases}\sf{ \green{Object\:exerts\: pressure = }50N/m^2 \: }\\\sf{ \green{Area\:of\: contact = 0.2\:m^2}\: }\end{cases}}$

$\pink{\bf{Need\:To\:Find}\begin{cases}\sf{ \green{Force = \:?}\: }\end{cases}}$

$\bf{\underline{\underline{Explanation:-}}}$

$\underline\mathtt \orange{Formula\:used\:here:-}$

• $\bigstar \: \boxed{ \sf \: Pressure = \frac{Force}{Area } }$

$\underline \mathtt \orange{Now,Putting\:the\:values:-}$

$\longrightarrow\sf \: 50 = \frac{Force}{0.2} \\ \\ \\ \longrightarrow\sf \: Force = 50 \times 0.2 \\ \\ \\ \ \longrightarrow\sf \: Force = 10N$

$\underline \mathtt \orange {Hence:-}$

• The force = 10 N

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$