Calculate the force is exerted by an iron nail on the hammer of 500 gram with a velocity of 30 m /sec hammer strike on the nail.
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Mass of the hammer (m) = 500 g = 0.5 kg
The initial velocity of the hammer (u) = 50 m/s
The nail takes time to stop the hammer (t) = 0.01 s
The velocity of the hammer (v) = 0 (since the hammer finally comes to rest)
From Newton’s second law of motion
f = m (v – u) / t
Where f = force
f = 0.5 × (0 – 50) / 0.01
f = -2500 N
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