Calculate the force of an electron of charge 1.6*10^-19C situated in a uniform electric field of intensity 120N\C
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Step-by-step explanation:
1.6×10 18 m/s 2
Step 1 : Force on electron due to electric field F=q e E
(1) Step 2 : Acceleration produced: We know that, F=ma ⇒a= m F Using equation (1) a= m e q e E = 9.1×10 −31 Kg (9.1×10 6 N/C)×(1.6×10 −19 C) =1.6×10 18 m/s 2 Hence, acceleration of electron is 1.6×10 18 m/s 2
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