calculate the force of an object of mass 12 KG which velocity change from 20 m per second to 80 m per second within 5 second
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Here is Your Answer.....!!!!!
_________________________
〽↖↖Actually welcome to the concept of the KINEMATICS OF A BODY ....
〽⤵Here given
〽⤵Mass = 12 kg
〽⤵Initial Velocity = 20 m/s
〽⤵Final Velocity = 80 m/s
〽⤵Time taken = 5 sec
〽↖↖.....Thus according to the concept of Newtons Second law of motion .....
〽⤵⤵FORCE = MASS × ACCELERATION. ...
〽⤵Thus here acceleration = v - u ÷ t
〽⤵=======》 a = 80 - 20 ÷ 5 =====》 a = 12 m/s^2 ....
〽↖↖thus. ... F = ma
〽↖↖F = (12) (12)
therefore we get
〽⤵⤵Force = 144 newtons ⚓
⤵F = 144 N....
_________________________________
Hope it helps u.....☺
Here is Your Answer.....!!!!!
_________________________
〽↖↖Actually welcome to the concept of the KINEMATICS OF A BODY ....
〽⤵Here given
〽⤵Mass = 12 kg
〽⤵Initial Velocity = 20 m/s
〽⤵Final Velocity = 80 m/s
〽⤵Time taken = 5 sec
〽↖↖.....Thus according to the concept of Newtons Second law of motion .....
〽⤵⤵FORCE = MASS × ACCELERATION. ...
〽⤵Thus here acceleration = v - u ÷ t
〽⤵=======》 a = 80 - 20 ÷ 5 =====》 a = 12 m/s^2 ....
〽↖↖thus. ... F = ma
〽↖↖F = (12) (12)
therefore we get
〽⤵⤵Force = 144 newtons ⚓
⤵F = 144 N....
_________________________________
Hope it helps u.....☺
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