Question

calculate the force of attraction acting between two particles, each of mass 1 kg , placed at a distance of one metre. ​

Answer 1

Given :

• Mass of first object, M = 1 kg

• Mass of another object, m = 1 kg

• Distance, r = 1 m

• Gravity= 6.7 × 10⁻¹¹ Nm²/kg²

To Find :

• The gravitational Force between two particles

Solution :

From Newton's Universal law of Gravitation :

$\bigstar \: \: \sf \: F = G \times \dfrac{M \times m}{ {r}^{2} }$

$\longrightarrow \sf \: \dfrac{6.67 \times {10}^{ - 11} \times 1 \times 1}{(1) ^{2} }$

$\longrightarrow \sf \: \dfrac{6.67 \times 1 \times 1 \times {10}^{ - 11} }{1 \times 1}$

$\longrightarrow \sf \: \dfrac{6.67 \times {10}^{ - 11} }{1}$

$\longrightarrow \sf \: 6.67 \times {10}^{-11} \: Newtons$

$\therefore$ It is obvious that the Gravitational force between two particles of 1 kg each and 1 m apart is 6.67 × 10⁻¹¹ Newtons and this is a very small force.

Answer 2

Answer:

6.673 × 10^-11 N

Explanation:

Using Newton's laws of gravitational:

Force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

F = G m1m2/r²

As per given condition we have m1 and m2 is 1 kg and r is 1 m. While tha value of G is 6.673 × 10^-11 Nm²/kg².

F = (6.673 × 10^-11 × 1 × 1)/(1)²

F = (6.673 × 10^-11)/1

F = 6.673 × 10^-11 N

Hence, the value of force is 6.673 × 10^-11 N.