Question

calculate the force of attraction between a body 5kg at a distance of 10cm from a mass of10kg.(G=6.7*10^-11 Nmkg^-2)

Answer 1

g=GMm/r^2

Where,

        M is mass of 1st object

And m is the mass of 2nd object

And r is the distance between their centres

Now,

g=(6.7*10^11)(5)(10)/0.1^2.          (10cm = 0.1m)

   =3.35*10^13/0.01

   =3.35*10^11 Nm/kg^2

Hope you understood

Answer 2

answer:- 3.35 x 10^-11

proof:-

 m1= 5 kg

 m2 = 10 kg

  distance between objects = 10 cm

 force of attraction = ???

  F= g m1 x m2 / d^2

    =6.7 x 10^-11 x 5 x 10 / (10)^2

    = 67 x 10^-11 x 5 x 10 / 100 x 10

    =  67 x 10^-11 / 20

    =6.7 x 10^-11 / 2

    = 3.35 x 10^-11