Question

Calculate the force of attraction between the earth and sun, given that mass of earth is 6×10^24kg and mass of sun is 2×10^30. The average distance between the two is 1.5 × 10^11m.
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Answer 1

Given :

$M_1$ =mass of sun=$2×{10}^{30}\:kg$

$M_2$=mass of earth=$6×{10}^{24}\:kg$

R= Avg. distance between the Earth and the Sun $=1.5×{10}^{11}\:m$

$G=6.7×{10}^{-11}\:N{m}^{2}/{kg}^{2}$

According to universal law of gravitation,

$\begin{gathered}F=\frac{G×M_1×M_2}{{r}^{2}}\\\\=\frac{6.7×{10}^{-11}×2×{10}^{30}×6×{10}^{24}}{{(1.5×{10}^{11})}^{2}}\\\\\\\underline{F=3.57×{10}^{22}\:N}\\\\\\\underline{\boxed{\sf{ F=3.57×{10}^{22}\:N}}} \end{gathered}$

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Answer 2

Answer:

Explanation:

given m1 = 6×10^24 , m2 = 2× 10^30, r = 1.5 ×  10^11 ,

we know that force of attraction between two bodies =

     F = g m1m2/r^2   g = 6.07 ×10^-11

      F = 6.07 ×10^-11 × 6×10^24 × 2×10^30/2.25×10^22