Question

Calculate the force of attraction between the Earth and the Sun, given that the mass of the earth is 6 × 10^24kg. The average distance between the two is 1.5 ×10^10mani.

Answer 1

_/\_Hello mate__here is your answer--

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GIVEN:---

M1 = Mass of the Sun = 2 × 10^30 kg

M2 = Mass of the Earth = 6 × 10^24 kg

R = Average distance between the Earth and the Sun = 1.5 × 10^11 m

G = 6.7 × 10^−11 Nm^2 kg^−2

According to the universal law of gravitational ,

F = G× M1 × M2/ r^2

(Put the values of all quantities, we get)

=6.7×10^−11×2×10^30×6×10^24/(1.5×10^11)^2

= 3.57 × 10^22 N

Hence, the force of gravitation between the Earth and the Sun is

3.57 × 10^22 N

I hope, this will help you.☺

Thank you______❤

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Answer 2

Answer:

Given :

$M_1$ =mass of sun=$2×{10}^{30}\:kg$

$M_2$=mass of earth=$6×{10}^{24}\:kg$

R= Avg. distance between the Earth and the Sun $=1.5×{10}^{11}\:m$

$G=6.7×{10}^{-11}\:N{m}^{2}/{kg}^{2}$

According to universal law of gravitation,

$\begin{gathered}F=\frac{G×M_1×M_2}{{r}^{2}}\\\\=\frac{6.7×{10}^{-11}×2×{10}^{30}×6×{10}^{24}}{{(1.5×{10}^{11})}^{2}}\\\\\\\underline{F=3.57×{10}^{22}\:N}\\\\\\\underline{\boxed{\sf{ F=3.57×{10}^{22}\:N}}} \end{gathered}$