Question

calculate the force of attraction between two charges +4 coulumb and -4 coulumb seperated by 8×10 to the power 3 m
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Answer 1

Answer:

QUESTION:

calculate the force of attraction between two charges +4 coulumb and -4 coulumb seperated by 8×10^3 m

GIVEN:

• q1=4 coulomb
• q2=-4 coulomb
• r=8×10^3 m

TO FIND:

electrostatic force of attraction, f

FORMULA:

according to coulomb's law of electrostatics,

f=(Kq1q2)/r^2

where,

• f..... electrostatic force
• q1 and q2 are charges
• k is the proportionality constant whose value is 9×10^9 C^2N^-2m^-2
• r.....distance of seperation

SOLUTION:

$f = \frac{kq1q2}{ {r}^{2} } \\ \\ = \frac{9 \times {10}^{9} \times (4)( - 4) }{ {(8 \times {10}^{3}) }^{2} } \\ \\ = \frac{ - 144 \times {10}^{9} }{64 \times {10}^{6} } \\ \\ = - 2.25 \times {10}^{3} \\ \\ = - 2250 \: newton$

force is 2250 Newton or 2.25 kilo Newton

the negative sign indicates that the force is attractive

NOTE:

• attractive force exist between two oppositely charged particles.

• repulsive force exist between two same charged particle