Question

Calculate the force of attraction between
two metal spheres each of mass 90 kg, if the
distance between their centres is 40 cm.
[G = 6.67 x 10-" N m'/kg²1
blution:
Even: mı = 90 kg, m2 = 90 kg,
r= 40 cm = 40 x 10-2 m,
G-667 x 10-11 Nm2/kg2​

Answer 1

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Answer 2

Answer:

The force of attraction between two metal spheres is equal to $1.35\times 10^{-9}N$.

Explanation:

Given:

$m_{1}=90kg\\ m_{2}=90kg$

$r=0.40m$

$G=6.67\times 10^{-11} Nm^{2}/kg^{2}$

Here,

As we all know, the gravitational constant is denoted as G.

The mass of the first sphere is denoted by $m_{1}$.

The mass of the second sphere is denoted by $m_{2}$.

The force of attraction between the spheres is denoted by F.

The distance between the spheres is denoted by r.

Now,

By the equation,

$F= \frac{Gm_{1} m_{2} }{r ^{2} } \\F= \frac{6.67\times 10^{-11} \times 90\times 90 }{0.40^{2} }\\ F=1.35\times 10^{-6}N$

So, the force of attraction between two metal spheres is equal to $1.35\times 10^{-6}N$.