Question

Calculate the force of attraction between
two metal spheres each of mass 90 kg, if the
distance between their centres is 40 cm.
[G = 6.67 x 10-" N m'/kg²1
blution:
Even: mı = 90 kg, m2 = 90 kg,
r= 40 cm = 40 x 10-2 m,
G-667 x 10-11 Nm2/kg2

Answer 1

$G = 6.67 \times {10}^{-11} \frac{N{m}^{2}}{k{g}^{2}} \\ m_{1} = 90kg \\ m_{2} = 90kg \\ d = 40 \times {10}^{-2} m \\ \\ \mathtt{According \: to \: the \: Newton's \: Law \: of \: Gravitation,} \\ \\ \Rightarrow \qquad F = \frac{Gm_{1}m_{2}}{{d}^{2}} \\ \\ \Rightarrow \qquad F = \frac{6.67 \times {10}^{-11} \times 81 \times {10}^{2}}{{(40 \times {10}^{-2})}^{2}} \\ \\ \Rightarrow \qquad F = \frac{540.27 \times {10}^{-9}}{16 \times {10}^{-2}} \\ \\ \Rightarrow \qquad F = \frac{540.27}{16} \times {10}^{-9+2} \\ \\ \Rightarrow \qquad F = 33.77 \times {10}^{-7} \\ \\ \bold{Answer : } \mathtt{\quad 33.77 \times {10}^{-7} \: Newtons}$

Answer 2

PLEASE MARK ME AS THE BRAINLIEST ANSWER AND DON'T FORGET TO FOLLOW ME I WILL FOLLOW YOU BACK ♥️❣️♥️