Question

Calculate the force of attraction between two spheres each of mass 1kg separated by 3metres.

Answer 1

Answer:

The gravitational force on two bodies in vacuum be \bold{6.67 \times 10^{-11} N}6.67×10−11N

Explanation:

The gravitational force is measured product of masses and gravitational constant in respect to distance between them, so, the gravitational  force required is calculated using formula of force on each as follows –

Given is the mass of one body m = 1 kg

Mass of other body M = 1 kg

Distance between them r = 1 m

Therefore, gravitational force is given by –

\bold{\mathrm{F}=\mathrm{G} \mathrm{M} \mathrm{m} / \mathrm{r}^{2}}F=GMm/r2

\begin{lgathered}\begin{array}{l}{\mathrm{F}=6.67 \times 10^{-11} \times 1 \times 1 / 1 \times 1} \\ {\mathrm{F}=6.67 \times 10^{-11} \mathrm{N}}\end{array}\end{lgathered}F=6.67×10−11×1×1/1×1F=6.67×10−11N

Answer 2

Answer:

I hope this will help you...

if incorrect then sorry...

Given that,

mass of first sphere =1 kg

mass of second sphere = 1 kg

we know that,

F = G×m1×m2 /r square

= 6.67 × 10^-11 × 1 ×1 / 3×3

= 6.67 ×10^-11 /9

= 7.41 × 10^-12 N

Answer: Force of attraction is 7.41 ×10^-12 Newton