Calculate the force of attraction due to earth on a child weighing 10kg standing on the ground. (Radius of the earth = 6.4 x 10 6 m,mass of the earth = 6 x 10 24 kg ; and G = 6.7 x 10 -11 N m 2 / kg 2 ) (98 Newtons)
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use the formula given below. F = GMm/r^2 . here F= force exerted by earth. G= Gravitational constant. M = mass of earth. m= mass of the boy. r= radius of earth.
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Answer:
Answer is 98(approx) Newton Because
Explanation:
M.a=6×10^24kg
M.b=10kg
R2=6.4×10^6m
G=6.67×10
Fg=G M×m/r^2 = 6.67×10^-11×6×10^24×10/(6.4×10^6)^2
=6.67×6×10^-11+24+1-12/6.4×6.4
=6.67×6×10^2/6.4×6.4, here decimal will cancel
=667×6×10^2/64×64
=97.705 or 98(approx)
hope you will like my answer
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