Question

calculate the force of gravitation between a man of mass 75 kg and his son of mass 50 kg if the distance between the centre is 2 metres
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Answer 1

Answer:-

Given:-

Mass of the man (M) = 75 kg

Mass of his son (m) = 50 kg

Distance between them (r) = 2 m

We know that,

Gravitational force (F) = GMm/R²

• where G is the gravitational constant (G = 6.67 × 10⁻¹¹ Nm²/kg² )

Hence,

$\implies \sf \: F = \frac{6.67 \times {10}^{ - 11} \times 75 \times 50 }{ {2}^{2} } \\ \\ \\ \implies \sf \: F = \frac{6.67 \times {10}^{ - 11} \times 75 \times 25}{2} \\ \\ \\ \implies \sf \: F =12506.25 \times {10}^{ - 11} \\ \\ \\ \implies \sf \: F = 1250625 \times {10}^{ - 2} \times {10}^{ - 11} \\ \\ \\ \implies \sf \: F = 12.50625 \times {10}^{5} \times {10}^{ - 2} \times {10}^{ - 11} \\ \\ \\ \implies \sf \: F = 12.50625 \times {10}^{5 - 2 - 11} \: \: \: \: ( \because \: {a}^{m} \times {a}^{n} = {a}^{(m + n)} ) \\ \\ \\ \implies \boxed{\sf F = 12.50625 \times {10}^{ - 8} \: \: N}$

∴ The gravitational force between the man and the son is 12.506 × 10⁻⁸ N.