Question

calculate the force of gravitation between a men weighing 80 kg 60 kg standing 2 meters apart

Answer 1

Solution:

Given:

$\sf{\implies M_{1}=80\;kg}$

$\sf{\implies M_{2}=60\;kg}$

$\sf{\implies Distance\;(r)=2\;m}$

To find:

=> Force of gravitation.

Formula used:

$\implies{\boxed{\sf{F = G\dfrac{m_{1}m_{2}}{r^{2}}}}}$

So, as we know that value of Gravitational constant is $\sf{6.7\times 10^{-11}\;N\;m^{2}/kg^{2}}$

Now, put the values in the formula,

$\sf{\implies F = G\dfrac{m_{1}m_{2}}{r^{2}}}$

$\sf{\implies F = \dfrac{6.7\times 10^{-11}\times 80\times 60}{2^{2}}}$

$\sf{\implies F = \dfrac{6.7\times 10^{-11}\times4800}{4}}$

$\large{\boxed{\boxed{\red{\sf{\implies F = 8.04\times 10^{-8}N}}}}}$

Answer 2

$\bold{\underline{\underline{Answer:}}}$

Force of Gravitation (F) = $\bold{8.004\times\:10^-8}$

$\bold{\underline{\underline{Step\:-\:by\:-\:step\:explanation:}}}$

Given :-

• Mass of a man ${m_1}$ = 80 kg
• Mass of another man ${m_2}$ = 60 kg
• Distance between the two men (r) = 2 m

To find :-

• Force of Gravitation (F)

Solution :-

The gravitational force between objects is calculated using the formula :

$\bold{F\:=\:G}$$\frac{m_1\:m_2}{r^2}$

Where,

F = Force of Gravitation

G = Gravitational Constant

$\bold{m_1}$ = Mass of the first object

$\bold{m_2}$ = Mass of the second object

r = Distance between the objects

$\bold{G\:=\:6.67\times\:10^{-11}\:N\:m^2\:kg^{-2}}$

Block in the values,

$\implies$ $\bold{F\:=\frac{6.67\times\:10^{-11}\times\:4800}{2^2}}$

$\implies$ $\bold{F\:=\frac{0.00000032016}{4}}$

$\implies$ $\bold{F\:=\:0.00000008004}$

Scientific notation :-

$\bold{F\:=\:8.004\times\:10^-8}$