Question

calculate the force of gravitation between earth and sun given the mass of Earth is =6.10 kg and sun =2.10 kg . the average distance between the two is =1.5​*10¹¹ m​

Answer 1

$\pink{\overbrace{\underbrace{\sf Given}} :-}$

ㅤㅤㅤ• mass of Earth (m1) = 6.10 kg

ㅤㅤㅤ• mass of Sun (m2) = 2.10 kg

ㅤㅤㅤ•ㅤ distance (d) = 1.5 × 10¹¹ m

$\pink{\overbrace{\underbrace{\sf To \: Find}}:-}$

ㅤ• Calculate the gravitational force

ㅤㅤ between Sun & Earth ?

$\pink{\overbrace{\underbrace{\sf Usable \: Formula}}:-}$

ㅤㅤㅤㅤㅤ$\large \boxed{\sf\red{Fg = \dfrac{G m1 m2}{d^{2}}}}$

here ,

ㅤㅤFg = gravitational force

ㅤㅤ G = gravitational constant

ㅤㅤㅤ = $\sf{6.67\times 10^{-11} \: \dfrac{Nm^{2}}{kg^{2}}}$

ㅤㅤm1 = mass of Earth

ㅤ m2 = mass of Sun

ㅤㅤ d = distance between two's

$\pink{\overbrace{\underbrace{\sf Solution}}:-}$

$\: \: \: \: \: \: \: \:$$\sf{Fg = \dfrac{6.67\times 10^{-11}\times 6.10\times 2.10}{(1.5\times 10^{11})^{2}}}$

$\: \: \: \: \: \: \: \:$$\sf{Fg = \dfrac{6.67\times 6.1\times 2.1\times 10^{-11}}{2.25\times 10^{22}}}$

$\: \: \: \: \: \: \: \:$$\sf{Fg = \dfrac{6.67\times 12.81}{2.25\times 10^{33}}}$

$\: \: \: \: \: \: \: \:$$\sf{Fg = \dfrac{6.7\times 12.8}{2.25\times 10^{33}}}$

$\: \: \: \: \: \: \: \:$$\sf{Fg = \dfrac{85.76\times 10^{-33}}{2.25}}$

$\: \: \: \: \: \: \: \:$$\sf{Fg = 38.12\times 10^{-33}}$

$\: \: \: \: \: \: \: \:$$\large \boxed{\sf\pink{Fg = 3.8 \times 10^{-32} \: N}}$