Question

Calculate the force of gravitation between two bodies each of mass 70kg and 14 cm appart

Answer 1

$\textbf{ Hello Mate! }$

Converting 14 cm into m = 14 / 100 m
=> 0.14 m

Force of gravitation = GMm / d²

$= \frac{6.67 \times {10}^{ - 11} \times 70 \times 70 }{{0.14}^{2}} \\ = \frac{6.67 \times {10}^{ - 11} \times 7 \times 7 \times {10}^{2} }{({14 \times {10}^{ - 2})}^{2} } \\ = \frac{6.67 \times 49 \times {10}^{ - 11 + 2 + 4 } }{196} \\ = 1.7\times {10}^{ - 5} newton$
$\boxed{ Answer = 1.7 × {10}^{-5} N }$

Have great future ahead!

Answer 2

Force of gravitation, F =(G×m₁×m₂)/r²

m₁=m₂=70 kg

r= distance between the bodies= 14cm =0.14m

Value of G=6.6738 x10⁻¹¹ N⋅m²/kg²

Force= [ ( 6.6738 x10⁻¹¹ ) × 70² ] / (0.14)²

= (6.6738 x10⁻¹¹ × 4900)/0.0196

= 3.2701x10⁻⁹ /0.0196

= 1.66841 ×10⁻⁷ N