calculate the force of gravitation between two dust particle of masses 1mg and 1kg separated by 1cm
Answers
Answered by
1
Explanation:
Given : m
1
=m
2
=1 kg, r=1 m
Force of gravitation F=
r
2
Gm
m
2
F=
1
2
6.67×10
−11
×1×1
=6.67×10
−11
N
Answered by
0
F=GmM/r^2
=6.673*10^-12(1*10^-6)(1)/(1*10^-2)^2
=6.673*10^-14N
Given
M=1kg
m=1mg=0.000001kg=1*10^-6kg
r=1cm=1*10^-2m
To Find
F=?
As we know the value of G=6.673*10^-12Nm^2/kg^2.
therefore by applying these values we get
F=6.673*10^-14N
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