Question

Calculate the force of gravitation due
to earth on a ball of 1 kg mass lying
on the ground. (mass of earth 6 X 1024 kg
Radius of earth = 6.4810om; and G= 6.7*10^-11

Nm²/kg ²)​

Answer 1

${{ \text{ \underline{ { \underline{Given \: data}}}}}:-}$

◐ Ball of 1 kg mass lying on the ground.

To Find :- Calculate the force of gravitation due to earth on a ball.

${{ \text{ \underline{ { \underline{Solution}}}}}:-}$

Here, we use formula to find, gravitational force between two particles.

${ \bf{ \dashrightarrow{F = G\frac{Mm}{ {R}^{2} } }}}$

◐ F = gravitational force between two particles.

◐ G = gravitational constant [6.7× 10^( -11 ) Nm²/kg²]

◐ M = mass of earth [6 × 10^(24) kg]

◐ m = mass of particle [ ball ]

◐ R = radius of earth [6371 km]

${ \small{\bf{ \dashrightarrow{F = 6.7 \times {10 }^{ - 11} \times \frac{6 \times {10}^{24} \times1 }{ {(6371)}^{2} } }}}}$

${ \small{\bf{ \dashrightarrow{F = \frac{4.02 \times {10}^{14} }{ 40589641 } }}}}$

${ \small{\bf{ \dashrightarrow{F = 9904004.81 \: N}}}}$

.....OR.....

${ \small{\bf{ \dashrightarrow{F = 9.904 \times {10}^{11} \: N}}}}$

Hence, 9.904 × 10¹¹ N force act's on ball.