Question

calculate the force of gravitation due to earth on a ball of 1 kg mass lying on the ground (mass of earth = 6×10²⁴ kg, radius of earth = 6.4 × 10³ km, and G=6.7 × 10-¹¹ Nm²/kg²)​

Answer 1

Answer:

Explanation:

Given :

• Mass of a ball (m) = 1 kg
• Mass of earth (M) = 6×10²⁴ kg
• Radius of earth (r) = 6.4 × 10³ km
• G = 6.67 × 10-¹¹ Nm²/kg²

To Find :

• The force of gravitation, F

Formula to be used :

• F = GMm/r²

Solution :

★Force of gravitation,

F = GMm/r²

⟶ F = 6.67 × 10-¹¹ × 6 × 10²⁴ ×1 / (6.4 × 10³)²

⟶ F = 6.67 × 10-¹¹ × 6 × 10²⁴/ 4.096 × 10⁷

⟶ F = 1.62841796875 × 10-¹¹ × 6 × 10¹⁷

⟶ F = 9.7705078125 × 10-¹¹ × 10¹⁷

⟶ F = 9.7705078125 × 10⁶ N

Hence, the force of gravitation is 9.7705078125 × 10⁶ N.