Question

Calculate the force of gravitation due to earth on a ball of 1 kg mass lying on the ground.( given mass of earth is 6*10 to the power 24 and radius of the earth is 6.4*10 to the power 3 and G= 6.67*10 to the power -11

Answer 1

F=GMm /R^2  M=Mass of the earth =6 x10*24kg  m=mass of the body=1kg,R= Radius of the earth=6.4 x10*3m,G=Gravitational constant=6.67 x10*-11Nm*2/kg*2   then F=6.67 x10*-11x6 x10*24 x1/6.4 x6.4 x10*3 x10*3 =6.67 x6 x10*13/6.4 x6.4 x10*6 =667 x6 x10*7/64 x64=0.97705 x10*7 =9.7705 x10*6N

Answer 2

Answer:

F=9.8 N

Explanation:

The force of gravitation is calculated by using the formula (F=G×M

HERE ,

●GRAVITATIONAL CONSTANT (G)=6.7×10^-11

●MASS OF EARTH(M)=6×10^24

●MASS OF BALL(m)=1Kg

AND DISTANCE BETWEEN CENTER,(r)=RADIUS OF EARTH AND THE BALL

=6.4×10^3 KM

=6.4×10^3×1000 M

=6.4×10^6

NOW,

PUTTING THESES VALUES IN THE ABOVE FORMULA,WE GET

F=6.7×10^-11×6×10^24×1/(6.4×10^6)^2

OR F=9.8 NEWTOWNS

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