Question

Calculate the force of gravity (g) acting on your friend of mass 60 kg. given mass of the earth is 6 x 1024 kg and the radius of the earth is 6.4 x 106m.
The best and the correct answer gets the BRAINLIEST !! this is my promise.

Answer 1

EXPLANATION.

• GIVEN

gravity acting on your friend of mass = 60kg

mass of earth = 6 X 10^24 kg

radius of the earth = 6.4 X 10^6 m

TO FIND FORCE OF GRAVITY.

Formula of gravitational force

$F \: = \frac{GM1M2}{ {r}^{2} }$

$f \: = \frac{6.67 \times 10 {}^{ - 11} \times 6 \times 10 {}^{24} \times 60 }{(6.4 \times 10 {}^{6} ) {}^{2} }$

$f \: = \frac{6 .67 \times 360 \times 10 {}^{13} }{6.6 \times 6.4 \times 10 {}^{12} }$

F = 588.9 N

Therefore,

force 588.9 N has acted on my friend.

Answer 2

Force 588.9N has acted on my friend.

Given :-

• Mass of your friend (m) = 60kg
• Mass of earth (M) = 6 × 10^24kg.
• Radius of earth (r) = 6.4 × 10^6 m.

To Find :-

• Calculate the force acted on your friend.

Solution :-

• As we know that

$\huge\tt \: F \: = G \: \frac{M \: m}{r {}^{2} }$

$\implies \large\tt \: F = \frac{6.67 \times 10 {}^{ - 11} \times 6 \times 10 {}^{24} \times 60 }{(6 \times 10 {}^{6} ) {}^{2} }$

$\implies \large \tt \: F \: = \frac{6.67 \times 360 \times 10 {}^{( - 11 +24) } }{6.6 \times 6.4 \times 10 {}^{12} }$

$\implies \large \tt \: F \: = \frac{6.67 \times 360 \times 10 {}^{13 } }{6.6 \times 6.4 \times 10 {}^{12} }$

$\implies \large \tt \: \red{ F \: = 588.9N}$