Physics, asked by bidhanch, 6 months ago

Calculate the force of repulsion acting between two positive charges of magnitude 20 esu and 30 esu when they are kept at a distance of 2 centimetre in air.
Please solve...

Answers

Answered by jashpokiya27

2

Answer:

1 esu = 3.33 × 10^-12 C

now F= kq1 q2/ r^2

F = 1.5 ×10^-7 N

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