Calculate the force required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h
Answers
Answered by
4
m=1500kg
u= 60km/h =60* 5/18 = 50/3m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 15000{0- (50/3)2}
= -208333.33J
hope this helps☺☺
u= 60km/h =60* 5/18 = 50/3m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 15000{0- (50/3)2}
= -208333.33J
hope this helps☺☺
Answered by
3
Hey there!
Given,
Mass of car (m) = 1500 kg
Velocity of car ( v) = 60 km/h = 60 * 5/18 m/s
Work done = ?
Here,
Work done = Kinetic Energy
= 1/2 * mv²
= 1/2 * 1500 * 60 * (5/18) J
= 20.8 × 10⁴ J (←Answer)
Hope It Helps You!
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