Question

Calculate the force required to imapart a car velocity 20m/s in 8 seconds given that the mass of the car is 1200 kg

Answer 1

✯ Force = 3000 N ✯

Explanation:

Given:

• Final velocity (v) = 20 m/s
• Time taken (t) = 8 sec
• Mass of the car (m) = 1200 kg

To find:

• Force required to impact the car.

Solution:

• Initial velocity (u) = 0 m/s

We know that,

✯ v = u + at ✯

• [ put values ]

$\implies$ 20 = 0 + a×8

$\implies$ 8a = 20

$\implies$ a = 20/8

$\implies$ a = 5/2

Therefore, the acceleration of the car is 5/2 m/s².

Now find the force required to impact the car.

We know that,

✯ F = ma ✯

• [ put values]

$\implies$ F = 1200× 5/2

$\implies$ F = 600 × 5

$\implies$ F = 3000

Therefore, the force required to impact the car is 3000 N.

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Answer 2

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Correct Question :-

Calculate the force required to impact a car velocity 20 m/s in 8 seconds given that the mass of the car is 1200 kg

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Given :-

• Velocity 20m/s in 8 seconds given that the mass of the car is 1200 kg

To Calculate :-

• The force required to impact the car

Solution :-

We have,

• Final Velocity(v) = 20 m/s
• Initial Velocity(u) = 0 m/s
• Time taken(t) = 8 s
• Mass of the car(m) = 1200 kg

We know that,

$\boxed{\tt{a = \dfrac{v - u}{t}}}$

Where,

• a = Acceleration
• v = Final Velocity
• u = Initial Velocity
• t = Time taken

Substituting the values we get,

$:\implies\tt{a = \dfrac{20 - 0}{8}}$

$:\implies\tt{a = \dfrac{\cancel{20}}{\cancel{8}}}$

$:\implies\tt{a = \dfrac{5}{2}}$

$\therefore\bf The \: acceleration \: is \: \dfrac{5}{2} \: m/s^{2}$

Now, we need to find the force required to impact the car

We know that,

$\boxed{\tt{F = ma}}$

Where,

• F = Force
• m = Mass
• a = Acceleration

Substituting the values we get,

$:\implies\tt{F = \cancel{1200} \times \dfrac{5}{\cancel{2}}}$

$:\implies\tt{F = 600 \times 5}$

$:\implies\pink{\bf{F = 3000}}$

$\therefore\bf{The \: force \: required \: to \: impact \: the \: car \: is \: 3000 \: N}$