Question

calculate the force required to impart a velocity of 30m/s in 10 sec ,if the mass of the body is 1.5 ton

pliz help me i have exm tomorrow​

Answer 1

Answer:

holla

When a car starts from the rest, its initial velocity is 0 and here its moving velocity is mentioned to be 30m/s.

So the difference in these two velocities is 30 – 0 = 30 m/s.

Hence, the acceleration of the car is calculated as this difference in velocities / time,

means here it is 30 / 10 = 3. 

The formula for finding the force is acceleration x mass, i.e. 1500 x 3 = 4500 Newton. 

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{ Force\:applied=4500\:N}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a body of mass 1.5 ton and its final velocity and time is given.

• We have to Calculate the force required to impart a velocity of 30m/s in 10 sec.

$\green{\underline\bold{Given :}} \\ :\implies \text{Mass \: of \: body = 1.5 \: ton} \\ \\ :\implies \text{Initial \: velocity(u) = 0} \\ \\ :\implies \text{Final \: velocity (v)= 30 \: m/s} \\ \\ :\implies \text{Time = 10 \: sec} \\ \\ \red{\underline \bold{To \: Find : }} \\ :\implies \text{Force \: required = ?}$

• According to given question :

$\bold{mass = 1.5 \: ton = 1500 \: kg} \\ \\ \bold{ By \: formula \: of \: force : } \\ :\implies F = ma - - - - - (1)\\ \\ \bold{F = Force} \\ \bold{m = Mass} \\ \bold{ a = Acceleration} \\ \\ \bold{by \: first \: equation \: of \: motion : }\\ :\implies v = u + at \\ \\ :\implies v - u = at \\ \\ \green{:\implies {a = \frac{v - u}{t} }}- - - - - (2) \\ \\ \bold{Putting \: value \: of \: a \: in \: (1)} \\ :\implies F = m \times \frac{v - u}{t} \\ \\ :\implies F = 1500 \times \frac{3 \cancel{0 }- 0}{ \cancel{10}} \\ \\ :\implies F= 1500 \times 3 \\ \\ \green{:\implies F= 4500 \: N} \\ \\ \green{\therefore{\text{ Force \: applied \: to \: move \: the \: body }}} \\ \: \: \: \green{\text{at \: 30 \: m/s \: is \: 4500 \: N}}$